Chemical companies are always looking to develop new and valuable
products to bring to market and to improve
the way they make existing
products to increase their profitability, reduce environmental pollution and also to try and ensure that any new products are produced in a sustainable way; that is one which meets the needs of current generation without compromising the ability of future generations to meet their own needs.
Chemists and chemical engineers will study a number of factors involved in manufacturing
a new
product before any large scale production takes place. Some of the most important factors are:
Atom economy - does the reaction produce more than one product? How much of the reactant atoms end up in the desired product?
The rate of the proposed reaction; is the reaction a fast or very slow one?
Does the reaction go to completion or is it a reversible reaction, which forms an equilibrium mixture of reactants and products? Mixtures of products will incur additional expense due to separation problems, the desired products will have to be separated out of the equilibrium mixture.
The image below summarises what an ideal chemical reaction might look like:
Atom economy- why is it important?
Let's suppose that a chemical company intends to start manufacturing a new product which they hope will to bring to market and sell to increase their profits, let's call this new product; product C. Now the chemists working for this particular chemical company have come up with two separate methods to make this new product C; these two methods are shown below:
Method 1
A + B → C
Method 2
D + E ⇌ C + F
So which method would you choose to make the new product C? Which method do you think will be the most profitable, sustainable and environmentally friendly? Let's look at some of the advantages and disadvantages for each of the proposed methods.
Advantages and disadvantages of each method
Method 1 has one major advantage over method 2, method 1 only produces the desired product C.
This means that all of the reactants are going into making the desired product and no other unwanted products are formed. This method also goes to completion, the arrow (→) used in the equation indicated that ALL of the reactants are turned into the desired product C. This is excellent since if there is only one product formed then there will be no expense incurred as a result of separation issues which would be the case if the reaction produced a mixture of two or more products. There is also no waste to be disposed of, which is likely to be both expensive and also environmentally unfriendly to dispose of.
Method 2 produces an unwanted product; product F. This product may be able to be sold
for profit but is could also be a wasteproduct with little or no value. The other problem with method 2 is that the
desired product C will have to be separated from the unwanted or waste product F and since this reaction is a reversible one not only will the unwanted product F be present but also unreacted reactants D and E will also be present, that is the reaction mixture will consist of an equilibrium mixture of reactants and products. This means a separation plant will have to be
built to separate out the desired product C from this equilibrium mixture and this will incur a cost both financially and environmentally.
Other factors to consider
The goal of any good chemist is to design a process where the maximum amount of the desired product is obtained with as little
waste and undesired products as possible being produced. That is the reaction should have a high percentage yield, it ideally should have a reasonable rate of reaction and not involve waiting for days or even longer before any reasonable amount of the desired product is produced.
Reactions which are reversible will obviously result an equilibrium mixture being produced which could mean separation issues and additional expense before any of the desired product is obtained. Any waste products produced will have to be disposed of and
this will incur costs both financial and environmental. Producing lots of unwanted products or waste materials also uses up valuable natural
resources and will cause additional environmental pollution both in their extraction and their disposal; these processes are likely to be unsustainable.
Calculating atom economy
One of the most important considerations in deciding which of the two methods above to use in producing the new product C is the atom economy or atom utilisation for each method. The atom economy or atom utilisation is used as a measure of how much of the reactants end up in the desired product; it can be calculated using the formula shown in the box below:
The higher the value of the atom economy the more of the reactants end up in the desired product, while any chemical reaction with a low atom economy is one where a large amount of the reactants end up in unwanted or waste products, this means that large amounts of reactants are likely to be need to manufacture small amounts of the desired product and lots of waste products will be formed; this is unlikely to be profitable, environmentally friendly and certainly not sustainable.
Example 1
As an example consider the fermentation of glucose to form the alcohol ethanol and carbon dioxide gas, word and symbolic equations for this reaction are shown below:
Now the relative formula masses of all the reactants and products are:
Mr of glucose (C6H12O6) is 180
Mr of ethanol (C2H5OH) is 46
Mr of carbon dioxide (CO2) is 44
The symbolic equation shows that fermentation produces 2 moles of ethanol for every one mole of glucose, so the mass of 2 moles of ethanol is 46 x 2= 92g.
While glucose has a Mr of 180.
So to work out the atom economy of this fermentation reaction simply put the Mr values into the above formula for atom economy and we have:
So the
atom economy = (Mr of ethanolรท Mr of glucose) x 100%
= (92 รท 180 ) x 100% = 51.1%
The fermentation process has a relatively low atom economy of just over 51%, meaning that just over half of the mass of the reactants ends up in the desired product; the ethanol. Improving the atom economy of this reaction is very desirable in order to reduce the amount of waste or undesired product and make the process more sustainable and cost-effective.
Self-check
Review your understanding of atom economy by completing the activity below. Simply click or drag the statements into the true or false bins and click the check answers button when your done.
True or False: Atom Economy
Drag items into the bins or click an item, then click a bin.
Statements
Place into True / False
Example 2 - Making ammonia
Ammonia (NH3) is a very valuable substance; its main uses are in the manufacture of fertilisers and explosives.
Ammonia is made industrially in a process called the Haber process. Word and symbolic equations for the synthesis of ammonia in the Haber process are shown below:
nitrogen + hydrogen ⇌   ammonia
N2 + 3H2 ⇌   2NH3
The relative formula masses for all the reactants and products are:
nitrogen (N2) = 28
hydrogen (H2) = 2
ammonia (NH3) = 17
So to the atom economy = (34 รท 28 + 6) x 100% = 100%
Now since there is only one product; the ammonia; then all of the reactants must end up as products and so the atom economy will be 100%. So although this sounds ideal as a possible route to making ammonia on an industrial scale it does not tell the whole story. As was mentioned above atom economy is important in deciding if a chemical process will likely be profitable and sustainable, however it is not the only factor that needs to be considered.
The reaction shown to make ammonia is a reversible reaction and so will involve an equilibrium mixture of products and reactants; it just so happens in this particular reaction that the position of equilibrium lies very much to the left, that is in favour of the reactants. Finally the rate of the forward reaction is also very slow due to the fact that it has a large activation energy. So while atom economy is very important it is not the only factor that should be considered in deciding whether a reaction will be profitable, sustainable and environmentally friendly.
Self-check- atom economy calculator
Calculate the atom economy for the reactions in the questions below; press the check answer button when you are done.
Atom Economy Practice
Question: Calculate the atom economy (%) for the desired product in the equation below. Use the given Ar values. Give your answer to 1 decimal place.
Equation
Data
Given Ar
Mr (each species)
Key points
Chemical reactions with a high atom economy or atom utilisation are reactions where a large proportion of the reactants end up in the desired product.
Reactions with a high atom economy are likely to be profitable and sustainable.
Chemical reactions with a low atom economy are will require large amounts of reactants to make a small amount of the desired product and will likely produce large amounts of waste; which is environmentally unfriendly and likely to be expensive to dispose of.
Whether a chemical reaction goes to completion or results in the formation of an equilibrium mixture should also be considered when designing a route to manufacture a particular product. Although reactions with a low atom economy that produce valuable "waste" products are also likely to still be profitable.
Rates of reaction and percentage yields are also important considerations in deciding whether any particular reaction is likely to be profitable.
The image below shows two different chemical factories. One factory utilises reactions with high atom economies which produce little waste and which cause low levels of pollution; this factory also utilises all of the raw materials it consumes and so is sustainable. The other chemical factory does none of these things!!